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题目:
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
代码:
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { ListNode dummy(-1); ListNode *p = &dummy; while ( l1 && l2 ) { if ( l1->val<l2->val ) { p->next = l1; l1 = l1->next; } else { p->next = l2; l2 = l2->next; } p = p->next; } p->next = l1 ? l1 : l2; return dummy.next; } };
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原文地址:http://www.cnblogs.com/xbf9xbf/p/4511912.html