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public class Solution { public int threeSumClosest(int[] nums, int target) { if (nums == null || nums.length < 3) { return Integer.MAX_VALUE; } Arrays.sort(nums); int min = Integer.MAX_VALUE/2;//otherwise it will overflow for (min - target);
for (int i = 0; i < nums.length; i++) { int left = i + 1; int right = nums.length-1; while (left < right) { int sum = nums[i] + nums[left] + nums[right]; if (sum == target) { return target; } else if (sum < target) { left++; } else { right--; } min = Math.abs(sum - target) < Math.abs(min - target) ? sum : min; } } return min; } }
注意红字部分!,min 开始应该赋值为Integer.MAX_VALUE/2 否则后面的表达式(min - target)如果target为负数会溢出overflow
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原文地址:http://www.cnblogs.com/77rousongpai/p/4513501.html