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Design a data structure that supports the following two operations:
void addWord(word) bool search(word)
search(word) can search a literal word or a regular expression string containing only letters
a-z
or .
. A .
means it can represent any one letter.
For example:
addWord("bad") addWord("dad") addWord("mad") search("pad") -> false search("bad") -> true search(".ad") -> true search("b..") -> true
Note:
You may assume that all words are consist of lowercase letters a-z
.
[思路]
1. 用一个set存. 超时.
2. 用trie来存.
[CODE]
public class WordDictionary { Set<String> dict = new HashSet<String>(); // Adds a word into the data structure. public void addWord(String word) { dict.add(word); } // Returns if the word is in the data structure. A word could // contain the dot character '.' to represent any one letter. public boolean search(String word) { if(dict.contains(word) ) return true; else if(!word.contains(".")) return false; for(int c='a'; c<='z'; c++) { int i=0; while(word.charAt(i++) != '.'){} StringBuilder sb = new StringBuilder(word); sb.setCharAt(i-1, (char)c); if( search(sb.toString()) ) return true; } return false; } } // Your WordDictionary object will be instantiated and called as such: // WordDictionary wordDictionary = new WordDictionary(); // wordDictionary.addWord("word"); // wordDictionary.search("pattern");
leetcode : Add and Search Word - Data structure design
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原文地址:http://blog.csdn.net/xudli/article/details/45840001