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模拟 HDOJ 5095 Linearization of the kernel functions in SVM

时间:2015-05-19 18:29:02      阅读:180      评论:0      收藏:0      [点我收藏+]

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题目传送门

  1 /*
  2     题意:表达式转换
  3     模拟:题目不难,也好理解题意,就是有坑!具体的看测试样例。。。
  4 */
  5 #include <cstdio>
  6 #include <algorithm>
  7 #include <iostream>
  8 #include <cstring>
  9 #include <cmath>
 10 #include <string>
 11 #include <vector>
 12 #include <queue>
 13 #include <map>
 14 #include <set>
 15 #include <ctime>
 16 #include <cstdlib>
 17 using namespace std;
 18 
 19 const int MAXN = 1e4 + 10;
 20 const int INF = 0x3f3f3f3f;
 21 
 22 char s[] = {p, q, r, u, v, w, x, y, z};
 23 
 24 int main(void)        //HDOJ 5095 Linearization of the kernel functions in SVM
 25 {
 26     //freopen ("F.in", "r", stdin);
 27 
 28     int t;    scanf ("%d", &t);
 29     while (t--)
 30     {
 31         int a[11];    bool first = false;    int j = -1;
 32         for (int i=1; i<=10; ++i)    scanf ("%d", &a[i]);
 33         for (int i=1; i<=10; ++i)
 34         {
 35             j++;
 36             if (!a[i])    continue;
 37             if (a[i] > 0 && first)    putchar (+);
 38 
 39             if (a[i] == -1)
 40             {
 41                 if (i < 10)    putchar (-);
 42                 else    printf ("-1");
 43             }
 44             else
 45             {
 46                 if (a[i] == 1)
 47                 {
 48                     if (i == 10)    putchar (1);
 49                 }
 50                 else printf ("%d", a[i]);
 51             }
 52 
 53             first = true;
 54             if (j <= 8)    printf ("%c", s[j]);
 55         }
 56         if (!first)    printf ("0");
 57         puts ("");
 58     }
 59 
 60     return 0;
 61 }
 62 
 63 /*
 64 21
 65 0 46 3 4 -5 -22 -8 -32 24 27
 66 2 31 -5 0 0 12 0 0 -49 12
 67 0 1 0 0 0 0 0 0 0 -1
 68 0 0 0 0 0 0 0 0 0 0
 69 0 0 0 0 0 0 0 0 0 1
 70 1 -1 1 -1 1 1 1 1 1 0
 71 0 46 3 4 -5 -22 -8 -32 24 27
 72 2 31 -5 0 0 12 0 0 -49 12
 73 0 0 0 0 0 0 0 0 0 0
 74 1 2 3 4 5 6 7 8 9 10
 75 -1 2 3 -5 8 3 0 6 9 20
 76 1 -1 1 1 1 -1 -1 -1 0 0
 77 10000 123 123 123 456 12354 123 12345  45 10110
 78 0 0 0 1 2 3 -1 -2 -3 56
 79 0 0 0 -1 -2 0 0 1 23 45
 80 */
 81 
 82 /*
 83 46q+3r+4u-5v-22w-8x-32y+24z+27
 84 2p+31q-5r+12w-49z+12
 85 q-1
 86 0
 87 1
 88 p-q+r-u+v+w+x+y+z
 89 46q+3r+4u-5v-22w-8x-32y+24z+27
 90 2p+31q-5r+12w-49z+12
 91 0
 92 p+2q+3r+4u+5v+6w+7x+8y+9z+10
 93 -p+2q+3r-5u+8v+3w+6y+9z+20
 94 p-q+r+u+v-w-x-y
 95 10000p+123q+123r+123u+456v+12354w+123x+12345y+45z+10110
 96 u+2v+3w-x-2y-3z+56
 97 -u-2v+y+23z+45
 98 -u-2v+y+23z+45
 99 -u-2v+y+23z+45
100 -u-2v+y+23z+45
101 -u-2v+y+23z+45
102 -u-2v+y+23z+45
103 -u-2v+y+23z+45
104 */

 

模拟 HDOJ 5095 Linearization of the kernel functions in SVM

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原文地址:http://www.cnblogs.com/Running-Time/p/4514897.html

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