leetcode 201: Bitwise AND of Numbers Range

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Bitwise AND of Numbers Range

Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive.

For example, given the range [5, 7], you should return 4.

[思路]

等价于 求 m 与 n 二进制编码中 同为1的前缀.

[CODE]

public class Solution {
    public int rangeBitwiseAnd(int m, int n) {
        int bit = 0;
        while(m!=n) {
            m>>=1;
            n>>=1;
            bit++;
        }
        return m<<bit;
    }
}

leetcode 201: Bitwise AND of Numbers Range

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原文地址：http://blog.csdn.net/xudli/article/details/45912649