码迷,mamicode.com
首页 > 其他好文 > 详细

encoding(hdoj1020)

时间:2015-05-22 14:49:24      阅读:100      评论:0      收藏:0      [点我收藏+]

标签:

Problem Description
Given a string containing only ‘A‘ - ‘Z‘, we could encode it using the following method:

1. Each sub-string containing k same characters should be encoded to "kX" where "X" is the only character in this sub-string.

2. If the length of the sub-string is 1, ‘1‘ should be ignored.
 
Input
The first line contains an integer N (1 <= N <= 100) which indicates the number of test cases. The next N lines contain N strings. Each string consists of only ‘A‘ - ‘Z‘ and the length is less than 10000.
 
Output
For each test case, output the encoded string in a line.
 
Sample Input
2
ABC
ABBCCC
 
Sample Output
ABC
A2B3C
 1 #include<stdio.h>
 2 #include<string.h>
 3 int main()
 4 {
 5     char a[10001];
 6     int n;
 7     scanf("%d",&n);
 8     getchar();
 9     while(n--)
10     { 
11         memset(a,0,sizeof(a));
12         gets(a);
13         int len=strlen(a),i,count=1;
14         for(i=0;i<len-1;i++)
15         {
16             if(a[i]==a[i+1])
17             {
18                 count++;
19                 if(i==len-2)
20                     printf("%d%c",count,a[i]);        
21             }
22             else
23             {
24                 if(i==len-2)
25                     {
26                         if(count==1)
27                             printf("%c%c",a[i],a[i+1]);
28                         else
29                             printf("%d%c%c",count,a[i],a[i+1]);
30                     }
31                 else
32                     {
33                         if(count==1)
34                             printf("%c",a[i]);
35                         else
36                             printf("%d%c",count,a[i]);
37                     }
38                     count=1;
39             }
40         }
41         printf("\n");
42     }
43 }

 

encoding(hdoj1020)

标签:

原文地址:http://www.cnblogs.com/a1225234/p/4522123.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!