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64 Minimum Path Sum

时间:2015-05-23 06:27:29      阅读:87      评论:0      收藏:0      [点我收藏+]

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public class Solution {
    public int minPathSum(int[][] grid) {
        if (grid == null || grid.length == 0) {
            return 0;
        }
        int[][] min = new int[grid.length][grid[0].length];
        min[0][0] = grid[0][0];
        
        for (int i = 1; i< grid.length; i++) {
            min[i][0] = min[i - 1][0] + grid[i][0];
        }
        for (int j = 1; j < grid[0].length; j++) {
            min[0][j] = min[0][j - 1] + grid[0][j];
        }
        
        for (int i = 1; i< grid.length; i++) {
            for (int j = 1; j < grid[0].length; j++) {
                min[i][j] = Math.min(min[i -1][j], min[i][j - 1]) + grid[i][j];
            }
        }
        return min[grid.length -1][grid[0].length - 1];
    }
}

DP

min[i][j]= Math.min(min[i-1][j], min[i][j -1]) + grid[i][j]

64 Minimum Path Sum

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原文地址:http://www.cnblogs.com/77rousongpai/p/4523631.html

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