标签：杭电   acm   

I NEED A OFFER!

10 3
4 0.1
4 0.2
5 0.3
0 0

44.0%

Hint
You should use printf("%%") to print a ‘%‘.

01背包。这里有个小技巧，就是转化为求收不到一份offer的最小概率。

AC代码如下：

#include<iostream>
#include<cstdio>
using namespace std;

double min(double a,double b)
{
    return a<b?a:b;
}

int main ()
{
    int n,m,a[10005];
    int i,j;
    double b[10005],c[10005],dp[10005];
    while(~scanf("%d%d",&n,&m)&&(n||m))
    {
        for(i=1;i<=m;i++)
        {
            scanf("%d%lf",&a[i],&b[i]);
            c[i]=1.0-b[i];
        }
        for(i=0;i<=n;i++)
            dp[i]=1.0;
        for(i=1;i<=m;i++)
            for(j=n;j>=a[i];j--)
            dp[j]=min(dp[j-a[i]]*c[i],dp[j]);
        printf("%.1lf%%\n",(1.0-dp[n])*100);

    }
    return 0;
}

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杭电 1203 I NEED A OFFER!

标签：杭电   acm   

原文地址：http://blog.csdn.net/hanhai768/article/details/30741923