标签:
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4768 Accepted Submission(s): 1563
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<cstdlib>
#include<algorithm>
#include<queue>
#include<vector>
#include<set>
#include<stack>
using namespace std;
vector<int> e[2010];
stack<int> s;
int n,m;
int Dfs[2010],use[1010],low[1010],isstack[1010];
int top,newflag;
void init()
{
memset(Dfs,0,sizeof(Dfs));
memset(use,0,sizeof(use));
memset(low,0,sizeof(low));
memset(isstack,0,sizeof(isstack));
for(int i=0;i<2*n;i++)
e[i].clear();
while(!s.empty())
s.pop();
}
void tarjan(int u)
{
Dfs[u]=low[u]=++top;
isstack[u]=1;
s.push(u);
for(int i=0;i<e[u].size();i++)
{
int v=e[u][i];
if(!Dfs[v])
{
tarjan(v);
low[u]=min(low[u],low[v]);
}
else if(isstack[v])
low[u]=min(low[u],Dfs[v]);
}
if(Dfs[u]==low[u])
{
newflag++;
int x;
do
{
x=s.top();
s.pop();
use[x]=newflag;
isstack[x]=0;
}while(x!=u);
}
}
int main()
{
int a,b,c,d;
while(scanf("%d%d",&n,&m)!=EOF)
{
init();
for(int i=1;i<=m;i++)
{
scanf("%d%d%d%d",&a,&b,&c,&d);
int u,v;
u=2*a+c,v=2*b+d;
e[u].push_back(v^1);
e[v].push_back(u^1);
}
for(int i=0;i<2*n;i++)
{
if(!Dfs[i])
tarjan(i);
}
bool flag=true;
for(int i=0;i<n;i++)
{
if(use[2*i]==use[(2*i)^1])
{
flag=false;
break;
}
}
if(flag)
{
printf("YES\n");
}
else
printf("NO\n");
}
return 0;
}
标签:
原文地址:http://www.cnblogs.com/water-full/p/4531399.html