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0 1 2 3 4 5
no no yes no no no
#include <iostream> #include <cstdio> #include <cmath> using namespace std; int main() { long n; while(scanf("%ld",&n) != EOF) if (n%8==2 || n%8==6) printf("yes\n"); else printf("no\n"); return 0; }
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原文地址:http://blog.csdn.net/zp___waj/article/details/46041703