标签:c++ 生活
*作者:王忠
*完成日期:2015.5.27
*版本号:v1.0
*
*问题描述:(1)先建立一个Point(点)类,包含数据成员x,y(坐标点);
(2)以Point为基类,派生出一个Circle(圆)类,增加数据成员(半径),基类的成员表示圆心;
(3)编写上述两类中的构造、析构函数及必要运算符重载函数(本项目主要是输入输出);
(4)定义友元函数int locate,判断点p与圆的位置关系(返回值<0圆内,==0圆上,>0 圆外);
*输入描述:
*程序输出:
#include<iostream> #include<Cmath> using namespace std; class Point //定义坐标点类 { public: Point():x(0),y(0) {}; Point(double x0, double y0):x(x0), y(y0) {}; friend ostream& operator <<(ostream &output,Point &p); double distance(Point &p); protected: double x,y; //点的横坐标和纵坐标 }; class Circle:public Point { public: Circle(double x,double y,double z):Point(x,y),r(z) {} friend istream& operator >>(istream &input,Circle &c); friend ostream& operator <<(ostream &output,Circle &c); friend int locate(Point &p, Circle &c); protected: double r; }; ostream& operator <<(ostream &output,Point &p) { output<<"Point: ("<<p.x<<","<<p.y<<")"<<endl; return output; } double Point::distance(Point &p) { double dx = x-p.x; double dy = y-p.y; return sqrt(dx*dx+dy*dy); } istream& operator >>(istream &input,Circle &c) { double a,b,d; cout<<"输入半径,圆心坐标:"; input>>a>>b>>d; Circle(a,b,d); return input; } ostream& operator <<(ostream &output,Circle &c) { output<<"Circle: ("<<c.r<<","<<c.x<<","<<c.y<<")"<<endl; return output; } int locate(Point &p,Circle &c) { Point cp(c.x,c.y); double d = cp.distance(p); if (d==c.r) return 0; else if (d < c.r) return -1; else return 1; } int main( ) { Circle c1(3,2,4),c2(4,5,5); //c2应该大于c1 Point p1(1,1),p2(3,-2),p3(7,3); //分别位于c1内、上、外 cout<<"圆c1: "<<c1; cout<<"点p1: "<<p1; cout<<"点p1在圆c1之"<<((locate(p1, c1)>0)?"外":((locate(p1, c1)<0)?"内":"上"))<<endl; cout<<"点p2: "<<p2; cout<<"点p2在圆c1之"<<((locate(p2, c1)>0)?"外":((locate(p2, c1)<0)?"内":"上"))<<endl; cout<<"点p3: "<<p3; cout<<"点p3在圆c1之"<<((locate(p3, c1)>0)?"外":((locate(p3, c1)<0)?"内":"上"))<<endl; return 0; }
标签:c++ 生活
原文地址:http://blog.csdn.net/wangzhongwangmin/article/details/46045071