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1 /*
2 字符串处理:回文串是串联的,一个一个判断
3 */
4 #include <cstdio>
5 #include <cstring>
6 #include <iostream>
7 #include <algorithm>
8 #include <string>
9 using namespace std;
10
11 const int MAXN = 1e3 + 10;
12 const int INF = 0x3f3f3f3f;
13 char s[MAXN];
14
15 bool check(int x, int y)
16 {
17 for (int i=x, j=y; i<j; ++i, --j)
18 {
19 if (s[i] != s[j]) return false;
20 }
21
22 return true;
23 }
24
25 int main(void) //Codeforces Round #305 (Div. 2) A. Mike and Fax
26 {
27 int k;
28 while (scanf ("%s", s) == 1)
29 {
30 scanf ("%d", &k);
31 int len = strlen (s);
32 if (len % k != 0) puts ("NO");
33 else if (len == 1 && k == 1) puts ("YES");
34 else
35 {
36 int m = len / k; bool flag = true;
37 for (int i=0; i<len; i+=m)
38 {
39 if (!check (i, i+m-1))
40 {
41 flag = false; break;
42 }
43 }
44 if (flag) puts ("YES");
45 else puts ("NO");
46 }
47 }
48
49 return 0;
50 }
字符串处理 Codeforces Round #305 (Div. 2) A. Mike and Fax
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原文地址:http://www.cnblogs.com/Running-Time/p/4534178.html