标签:topo排序
4 3 1 2 2 3 4 3
1 2 4 3
题解:topo排序 觉得没什么好说的。。代码加了注释 有问题看注释好了
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int maxn = 511;
int n, m; //n为顶点个数
int gra[maxn][maxn]; //邻接阵
int degree[maxn]; //记录顶点的入度
int main(){
while(scanf("%d%d", &n, &m)!=EOF){
memset(gra, 0, sizeof(gra));
memset(degree, 0, sizeof(degree));
int p1, p2;
for(int i = 0; i < m; ++i){
scanf("%d%d", &p1, &p2);
if(!gra[p1][p2]){
gra[p1][p2] = 1;
++degree[p2]; //入度+1
}
}
for(int i = 1; i <= n; ++i){ //遍历n次每次找出一个顶点
for(int j = 1; j <= n; ++j){ //遍历所有的结点
if(degree[j] == 0){
--degree[j]; //该顶点的入度为-1,防止该顶点被在此遍历到
if(i != n){
printf("%d ", j);
}
else{
printf("%d\n", j);
}
for(int k = 1; k <= n; ++k){
if(gra[j][k] == 1){
--degree[k]; //与该顶点关联的顶点的入度递减
}
}
break;
}
}
}
}
return 0;
}
标签:topo排序
原文地址:http://blog.csdn.net/u012431590/article/details/46053525