2 3 4 1 1 5 5 4 3 2 1
No Yes
代码
#include <stdio.h> int main() { long i,n; double max,number,sum; scanf("%d",&n); while(n--) { scanf("%d",&i); max=0; sum=0; while(i--) { scanf("%lf",&number); if(number>max) max=number; sum+=number; } sum-=max; if(max<=sum+1) printf("Yes\n"); else printf("No\n"); } return 0; }
原文地址:http://blog.csdn.net/blue_skyrim/article/details/46126049