(4)定义友元函数int locate,判断点p与圆的位置关系(返回值<0圆内,==0圆上,>0 圆外);
代码
#include <iostream> #include <cmath> using namespace std; class Point { protected: double x,y; public: Point(double xx,double yy):x(xx),y(yy) {} double getx(){return x;} double gety(){return y;} friend ostream & operator<<(ostream &,const Point &); }; ostream & operator<<(ostream &output,const Point &p) { output<<"["<<p.x<<","<<p.y<<"]"<<endl; return output; } class Circle:public Point { protected: double r; public: Circle(double xx,double yy,double rr):Point(xx,yy),r(rr) {} friend ostream &operator<<(ostream &out,Circle &c); friend int locate(Point &p,Circle &c); }; ostream &operator<<(ostream &out,Circle &c) { out<<"圆心=("<<c.getx()<<","<<c.gety()<<") 半径="<<c.r<<endl; return out; } int locate(Point &p,Circle &c) { double x=p.getx()-c.getx(),y=p.gety()-c.gety(),s; s=sqrt(x*x+y*y); if(abs(s-c.r)<=0.00001) return 0; else if(s>c.r) return 1; else return -1; } int main( ) { Circle c1(3,2,4),c2(4,5,5); //c2应该大于c1 Point p1(1,1),p2(3,-2),p3(7,3); //分别位于c1内、上、外 cout<<"圆c1: "<<c1; cout<<"点p1: "<<p1; cout<<"点p1在圆c1之"<<((locate(p1, c1)>0)?"外":((locate(p1, c1)<0)?"内":"上"))<<endl; cout<<"点p2: "<<p2; cout<<"点p2在圆c1之"<<((locate(p2, c1)>0)?"外":((locate(p2, c1)<0)?"内":"上"))<<endl; cout<<"点p3: "<<p3; cout<<"点p3在圆c1之"<<((locate(p3, c1)>0)?"外":((locate(p3, c1)<0)?"内":"上"))<<endl; return 0; }
原文地址:http://blog.csdn.net/blue_skyrim/article/details/46238921