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Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 327680/102400 K (Java/Others)
Total Submission(s): 17683 Accepted Submission(s):
6493
#include<stdio.h>
#include<string.h>
#define MAX 10000010
#define maxn(a,b)(a>b?a:b)
int set[MAX],path[MAX];
int a[100010],b[100010];
int sum=0;
int find(int fa)
{
int t;
int ch=fa;
while(fa!=set[fa])
fa=set[fa];
while(ch!=fa)
{
t=set[ch];
set[ch]=fa;
ch=t;
}
return fa;
}
void mix(int x,int y)
{
int fx,fy;
fx=find(x);
fy=find(y);
if(fx!=fy)
{
set[fx]=fy;
path[fy]+=path[fx];
if(sum<path[fy])
sum=path[fy];
}
}
int main()
{
int n,m,j,i,max,point;
while(scanf("%d",&n)!=EOF)
{
if(n==0)
{
printf("1\n");
continue;
}
max=0;
for(i=1;i<=n;i++)
{
scanf("%d%d",&a[i],&b[i]);
if(max<maxn(a[i],b[i]))
max=maxn(a[i],b[i]);
}
for(i=1;i<=max;i++)
{
set[i]=i;
path[i]=1;
}
for(i=1;i<=n;i++)
{
mix(a[i],b[i]);
}
printf("%d\n",sum);
sum=0;
}
return 0;
}
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原文地址:http://www.cnblogs.com/tonghao/p/4540170.html