Boudreaux and Thibodeaux are on the road again . . .

"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"

"Don‘t worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"

"We‘re not going to make it, I say!"

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

There will be exactly one line of output. This line will be:

   NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

   CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler). 
The height of the 18-wheeler is 168 inches.

180 160 170

CRASH 160

South Central USA 2003

We have carefully selected several similar problems for you:  1040 1032 1064 1038 1056 

HDU，最水，英语看的脑子都是大的.

题意是说输入三个数，如果三个数都比168大，那么输出NO CRASH；否则输出第一个出现小于等于168的那个数！

如果你能从这段英文看出这个意思来，恭喜你，你赢了。反正我是没看出来！！

#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
    int a,b,c;
    while(scanf("%d%d%d",&a,&b,&c)!=EOF)
    {
        if(a>168&&b>168&&c>168)
        {
            cout<<"NO CRASH"<<endl;
        }
        else if(a<168)
        {
            cout<<"CRASH "<<a<<endl;
        }
        else if(b<168)
        {
            cout<<"CRASH "<<b<<endl;
        }
        else if(c<168)
        {
            cout<<"CRASH "<<c<<endl;
        }
    }
    return 0;
}