[hiho 21]线段树-离散化

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题目描述

区间覆盖问题，区间绝对位置并不重要，重要的是各个更新的区间段之间的相对位置关系。

举例而言，离散化将区间更新[1,100], [2, 50]更换为区间更新[1,4], [2,3]。

离散化可以将空间复杂度从O(L)降到O(N)，进而也降低了更新和查询操作的复杂度。

用一个map来记录绝对位置与相对位置间的映射。

需要注意的是，离散化的线段树的叶子节点是[i, i+1]而不是[i, i]，区间分解时要考虑到这一点。

代码如下：

#include <stdio.h>
#include <cassert>
#include <algorithm>
#include <cstring>
#include <map>

#define N 100005

typedef
struct _seg_tree_ {
    int left, right;
    int val;
    bool lazy_tag;
    _seg_tree_ *lson = NULL, *rson = NULL;
    _seg_tree_(int left_idx, int right_idx, int value)
        : left(left_idx), right(right_idx), val(value), lazy_tag(false) {}
} seg_tree, *pseg_tree;

int data[2 * N];
int sorted_data[2 * N];
std::map<int, int> seq_map;
bool visible[N];

pseg_tree construct_seg_tree(int left, int right) {
    if (left + 1 == right) {
        return new seg_tree(left, right, 0);
    }
    int mid = left + (right - left) / 2;
    pseg_tree lson = construct_seg_tree(left, mid);
    pseg_tree rson = construct_seg_tree(mid, right);
    pseg_tree ans = new seg_tree(left, right, 0);
    ans->lson = lson;
    ans->rson = rson;
    return ans;
}

void lazy_down(pseg_tree proot) {
    proot->lazy_tag = false;
    if (proot->lson != NULL) {
        proot->lson->lazy_tag = true;
        proot->lson->val = proot->val;
    }
    if (proot->rson != NULL) {
        proot->rson->lazy_tag = true;
        proot->rson->val = proot->val;
    }
}

void query_seg_tree(pseg_tree proot) {
    if (proot->lazy_tag == true) {
        visible[proot->val] = true;
        return;
    }
    if (proot->lson != NULL) {
        query_seg_tree(proot->lson);
    }
    if (proot->rson != NULL) {
        query_seg_tree(proot->rson);
    }
}

void modify_seg_tree(pseg_tree proot, int left, int right, int val) {
    if (left == proot->left && right == proot->right) {
        proot->val = val;
        proot->lazy_tag = true;
        return;
    }
    int mid = proot->left + (proot->right - proot->left) / 2;
    if (proot->lazy_tag == true) {
        lazy_down(proot);
    }
    if (left >= mid) {
        modify_seg_tree(proot->rson, left, right, val);
    }
    else if (right <= mid) {
        modify_seg_tree(proot->lson, left, right, val);
    }
    else {
        modify_seg_tree(proot->rson, mid, right, val);
        modify_seg_tree(proot->lson, left, mid, val);
    }
}

int main(){
    int n, l;
    scanf("%d%d", &n, &l);
    for (int i = 0; i < n; i++) {
        scanf("%d%d", data + 2 * i, data + 2 * i + 1);
    }
    memcpy(sorted_data, data, 2 * n * sizeof(int));
    std::sort(sorted_data, sorted_data + 2 * n);
    int len = std::unique(sorted_data, sorted_data + 2 * n) - sorted_data;
    for (int i = 0; i < len; i++) {
        seq_map.insert(std::make_pair(sorted_data[i], i + 1));
    }
    pseg_tree proot = construct_seg_tree(1, len);
    for (int i = 0; i < n; i++) {
        int l = seq_map.find(data[2 * i])->second;
        int r = seq_map.find(data[2 * i + 1])->second;
        modify_seg_tree(proot, l, r, i + 1);
    }
    query_seg_tree(proot);
    int ans = 0;
    for (int i = 1; i <= n; i++) {
        if (visible[i]) ans++;
    }
    printf("%d\n", ans);
    
    return 0;
}

[hiho 21]线段树-离散化

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原文地址：http://www.cnblogs.com/xblade/p/4541694.html