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之前提到过,线段树之所以更新查询快,是因为区间更新有lazy标记使得不需要每次都操作到叶子节点。
但是如果要操作一个节点时,其父节点上的lazy标记应当被释放,否则该节点无法得到最新的正确结果。
因而lazy标记下放的策略是在需要操作某个节点的子节点时,将该节点的lazy标记全部下放。见第69行。
同时应当注意,给某个节点增加lazy标记时,不要忘了修改该节点的相关统计值。因为更新完该节点后还要马上修改其父节点的统计值。见第80行。
代码如下:
#include <stdio.h> #define N 100005 #define MODE_ADD 0 #define MODE_SET 1 typedef struct _seg_tree_ { int left, right; int add; int setv; int val; _seg_tree_ *lson = NULL, *rson = NULL; _seg_tree_(int left_idx, int right_idx, int value) : left(left_idx), right(right_idx), add(0), setv(-1), val(value) {} } seg_tree, *pseg_tree; pseg_tree construct_seg_tree(int left, int right) { if (left == right) { int val; scanf("%d", &val); return new seg_tree(left, right, val); } int mid = left + (right - left) / 2; pseg_tree lson = construct_seg_tree(left, mid); pseg_tree rson = construct_seg_tree(mid + 1, right); pseg_tree ans = new seg_tree(left, right, lson->val + rson->val); ans->lson = lson; ans->rson = rson; return ans; } void lazy_down(pseg_tree proot) { if (proot->setv != -1) { if (proot->lson != NULL) { proot->lson->setv = proot->setv; proot->lson->add = 0; proot->lson->val = proot->setv * (proot->lson->right - proot->lson->left + 1); proot->rson->setv = proot->setv; proot->rson->add = 0; proot->rson->val = proot->setv * (proot->rson->right - proot->rson->left + 1); } proot->setv = -1; } if (proot->add != 0) { if (proot->lson != NULL) { proot->lson->add += proot->add; proot->rson->add += proot->add; proot->lson->val += proot->add * (proot->lson->right - proot->lson->left + 1); proot->rson->val += proot->add * (proot->rson->right - proot->rson->left + 1); } proot->add = 0; } } void modify_seg_tree(pseg_tree proot, int left, int right, int val, int type) { if (left == proot->left && right == proot->right) { if (type == MODE_ADD) { proot->add += val; proot->val += val * (right - left + 1); } else { proot->setv = val; proot->val = val * (right - left + 1); proot->add = 0; } return; } int mid = proot->left + (proot->right - proot->left) / 2; lazy_down(proot); if (left > mid) { modify_seg_tree(proot->rson, left, right, val, type); } else if (right <= mid) { modify_seg_tree(proot->lson, left, right, val, type); } else { modify_seg_tree(proot->rson, mid + 1, right, val, type); modify_seg_tree(proot->lson, left, mid, val, type); } proot->val = proot->lson->val + proot->rson->val; } int main(){ int n, m; scanf("%d%d", &n, &m); pseg_tree proot = construct_seg_tree(0, n); int type, left, right, val; for (int i = 0; i < m; i++) { scanf("%d%d%d%d", &type, &left, &right, &val); modify_seg_tree(proot, left, right, val, type); printf("%d\n", proot->val); } return 0; }
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原文地址:http://www.cnblogs.com/xblade/p/4542781.html