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#include<cstdio>
#include<cstring>
#include<algorithm>
#include<vector>
#include<string>
#include<iostream>
#include<queue>
#include<cmath>
#include<map>
#include<stack>
#include<bitset>
using namespace std;
#define REPF( i , a , b ) for ( int i = a ; i <= b ; ++ i )
#define REP( i , n ) for ( int i = 0 ; i < n ; ++ i )
#define CLEAR( a , x ) memset ( a , x , sizeof a )
typedef long long LL;
typedef pair<int,int>pil;
const int INF = 0x3f3f3f3f;
const int MOD=1e9+7;
const int maxn=1e5+10;
int a[maxn],n,b[maxn+100];
LL dp[maxn],c[maxn+100];
int lowbit(int x)
{
return x&(-x);
}
void update(int x,LL val)
{
while(x<maxn)
{
c[x]=(c[x]+val)%MOD;
x+=lowbit(x);
}
}
LL query(int x)
{
LL sum=0;
while(x>0)
{
sum=(sum+c[x])%MOD;
x-=lowbit(x);
}
return sum;
}
int main()
{
while(~scanf("%d",&n))
{
int cnt=1;
CLEAR(c,0);
REPF(i,1,n)
{
scanf("%d",&a[i]);
b[cnt++]=a[i];
}
sort(b+1,b+cnt);
cnt=unique(b+1,b+cnt)-(b+1);
for(int i=1;i<=n;i++)
dp[i]=1;
LL ans=0;
for(int i=1;i<=n;i++)
{
int x=lower_bound(b+1,b+1+cnt,a[i])-b;
dp[i]=(dp[i]+query(x))%MOD;
update(x,dp[i]);
ans=(ans+dp[i])%MOD;
}
printf("%I64d\n",ans);
}
return 0;
}
/*
*/
POJ 2227 Find the nondecreasing subsequences(DP)
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原文地址:http://blog.csdn.net/u013582254/article/details/46334163