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Time Limit: 4000/2000 MS (Java/Others)
Memory Limit: 65536/32768 K (Java/Others)
1 #include<bits/stdc++.h> 2 using namespace std; 3 int n,m; 4 int pre[1001]; 5 int r[1001]; 6 int findset(int x) { 7 int r=x; 8 while(pre[r]!=r) r=pre[r]; 9 int i=x,j; 10 // 路径压缩 11 while(i!=r) { 12 j=pre[i]; 13 pre[i]=r; 14 i=j; 15 } 16 return r; 17 } 18 void join(int x,int y) { 19 int f1=findset(x),f2=findset(y); 20 // 按秩合并 21 if(r[f1]<=r[f2]) { 22 pre[f1]=f2; 23 if (r[f1]==r[f2]) r[f2]++; 24 } 25 else pre[f2]=f1; 26 } 27 int main() { 28 while(~scanf("%d",&n)&&n) { 29 scanf("%d",&m); 30 int ans=0; 31 memset(pre,0,sizeof(pre)); 32 memset(r,0,sizeof(r)); 33 for (int i=1;i<=n;++i) pre[i]=i; 34 for (int i=1;i<=m;++i) { 35 int x,y; 36 scanf("%d%d",&x,&y); 37 join(x,y); 38 } 39 for (int i=1;i<=n;++i) 40 if(pre[i]==i) ans++; 41 printf("%d\n",ans-1); 42 } 43 }
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原文地址:http://www.cnblogs.com/TonyNeal/p/hdu1232.html