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Time Limit: 2000/1000 MS (Java/Others)
Memory Limit: 65536/32768 K (Java/Others)
1 #include<bits/stdc++.h> 2 using namespace std; 3 int pre[100001],r[100001]; 4 bool vis[100001]; 5 bool flag=0; 6 int findset(int x) { 7 int r=x; 8 while(pre[r]!=r) r=pre[r]; 9 int i=x,j; 10 while(i!=r) { 11 j=pre[i]; 12 pre[i]=r; 13 i=j; 14 } 15 return r; 16 } 17 void join(int f1,int f2) { 18 if(r[f1]<=r[f2]) { 19 pre[f1]=f2; 20 if (r[f1]==r[f2]) r[f2]++; 21 } 22 else pre[f2]=f1; 23 } 24 int main() { 25 int a,b; 26 while(~scanf("%d%d",&a,&b)) { 27 for (int i=1;i<=100000;++i) pre[i]=i,r[i]=1; 28 memset(vis,0,sizeof(vis)); 29 if (a==-1&&b==-1) break; 30 if (a==0&&b==0) { 31 printf("Yes\n"); 32 continue; 33 } 34 int sign=0,minn=1000001,maxn=-1; 35 do { 36 minn=min(min(minn,a),b); 37 maxn=max(max(maxn,a),b); 38 vis[a]=vis[b]=1; 39 int f1=findset(a),f2=findset(b); 40 if(f1==f2) sign=-1; 41 else join(f1,f2); 42 scanf("%d%d",&a,&b); 43 if(a==0&&b==0) break; 44 }while(1); 45 if(sign==-1) { 46 printf("No\n"); 47 continue; 48 } 49 bool x=0; 50 for (; minn<=maxn; minn++) 51 if(vis[minn] && pre[minn]==minn) { 52 if(x==1) {x=0;break;} 53 else x=1; 54 } 55 if(x) printf("Yes\n"); 56 else printf("No\n"); 57 } 58 return 0; 59 }
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原文地址:http://www.cnblogs.com/TonyNeal/p/hdu1272.html