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基本思路:把 int 转换成string 借用stringstream 时间复杂度O(n)
1 class Solution { 2 public: 3 public: 4 bool isPalindrome(int x) { 5 6 stringstream ss; 7 ss<<x; 8 string str=ss.str(); 9 int sfront = 0; 10 int sback=str.length()-1; 11 while(sfront<sback) 12 { 13 if(str[sfront]!=str[sback]) 14 return false; 15 ++sfront; 16 --sback; 17 } 18 return true; 19 } 20 };
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原文地址:http://www.cnblogs.com/xiaoying1245970347/p/4550345.html