Design a data structure that supports the following two operations:
void addWord(word) bool search(word)
search(word) can search a literal word or a regular expression string containing only letters a-z
or .
.
A .
means it can represent any one letter.
For example:
addWord("bad") addWord("dad") addWord("mad") search("pad") -> false search("bad") -> true search(".ad") -> true search("b..") -> true
Note:
You may assume that all words are consist of lowercase letters a-z
.
</pre><pre name="code" class="java">public class WordDictionary { class TrieNode { // Initialize your data structure here. boolean isEnd = false; public TrieNode() { } TrieNode[] next; } TrieNode root = new TrieNode(); // Adds a word into the data structure. public void addWord(String word) { TrieNode current = root; for (int i = 0; i < word.length(); i++) { if (current.next == null) current.next = new TrieNode[26]; if (current.next[word.charAt(i) - 'a'] == null) current.next[word.charAt(i) - 'a'] = new TrieNode(); if (i == word.length() - 1) current.next[word.charAt(i) - 'a'].isEnd = true; current = current.next[word.charAt(i) - 'a']; } } // Returns if the word is in the data structure. A word could // contain the dot character '.' to represent any one letter. public boolean search(String word) { Queue<TrieNode> que = new LinkedList<>(); Queue<TrieNode> next = new LinkedList<>(); int i = 0; que.offer(root); while (!que.isEmpty() && i < word.length()) { char c = word.charAt(i); while (!que.isEmpty()) { TrieNode tn = que.poll(); if (c != '.') { if (tn.next == null||tn.next[c - 'a'] == null) continue; next.offer(tn.next[c - 'a']); } else { if (tn.next == null) continue; for (int j = 0; j < tn.next.length; j++) { if (tn.next[j] != null) next.offer(tn.next[j]); } } } i++; if (i == word.length()) { while (!next.isEmpty()) { if (next.poll().isEnd) return true; } return false; } else { Queue<TrieNode> tmp = que; que = next; next = tmp; if (que.isEmpty()) return false; } } throw new IllegalArgumentException(); } } // Your WordDictionary object will be instantiated and called as such: // WordDictionary wordDictionary = new WordDictionary(); // wordDictionary.addWord("word"); // wordDictionary.search("pattern");
Add and Search Word - Data structure design
原文地址:http://blog.csdn.net/guorudi/article/details/46352447