Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.
For example, given n = 3, a solution set is:
"((()))", "(()())", "(())()", "()(())", "()()()"
使用递归的思想。public void getParen(int left, int right, String str, List<String> list) { if (left == 0 && right == 0) { list.add(str); } else if (left == right) { str += "("; getParen(left - 1, right, str, list); } else { if (left > 0) { String strLeft = str + "("; getParen(left - 1, right, strLeft, list); } if (right > 0) { String strRight = str + ")"; getParen(left, right - 1, strRight, list); } } } public List<String> generateParenthesis(int n) { List<String> list = new ArrayList<String>(); String str = ""; getParen(n, n , str, list); return list; }
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原文地址:http://blog.csdn.net/u010378705/article/details/31394333