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题目链接:http://acm.acmcoder.com/showproblem.php?pid=2594
题意:求最长的串 同时是s1的前缀又是s2的后缀。输出子串和长度。
思路:kmp
代码:
#include <vector>
#include <string>
#include <algorithm>
#include <iostream>
#include <stdio.h>
#include <string.h>
using namespace std;
char s1[500010],s2[500010];
char ANS[500010];
void get_next(char x[], int m, int Next[])
{
int i, j;
j = Next[0] = -1;
i = 0;
while (i < m)
{
while (-1 != j && x[i] != x[j]) j = Next[j];
Next[++i] = ++j;
}
}
int Next[1001000];
int KMP(char x[], int m, char y[], int n)//x模式串 y主串
{
int i, j;
i = j = 0;
get_next(x, m, Next);
if (n > m) i = n - m;
while (i < n)
{
if (j == -1 || y[i] == x[j])
{
i++;
j++;
}
else j = Next[j];
}
return j;
}
int main()
{
while (cin>>s1>>s2)
{
int len1 = strlen(s1);
int len2 = strlen(s2);
int ans = KMP(s1, len1, s2, len2);
if (ans !=0 )
{
for(int i=0;i<ans;i++) cout<<s1[i];cout<<" ";
}
cout<<ans<<endl;
}
return 0;
}
hdu 2594 Simpsons’ Hidden Talents 【KMP】
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原文地址:http://blog.csdn.net/u014427196/article/details/46379531