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Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
The same repeated number may be chosen from C unlimited number of times.
Note:
For example, given candidate set 2,3,6,7
and target 7
,
A solution set is:
[7] [2, 2, 3]
解题分析:
class Solution { public: vector<vector<int> > combinationSum(vector<int> &candidates, int target) { vector<vector<int>> result; if (candidates.size() == 0) return result; sort(candidates.begin(), candidates.end()); // sort vector<int> path; dfs(candidates, target, 0, path, result); return result; } void dfs(const vector<int>& nums, int gap, int start, vector<int>& path, vector<vector<int>>& result) { if (gap == 0) { // 找到一个合法解 result.push_back(path); return; } for (int i = start; i < nums.size(); ++i) { // 扩展状态 if (gap < nums.at(i)) continue; // 剪枝 path.push_back(nums.at(i)); // 执行扩展动作 dfs(nums, gap - nums.at(i), i, path, result); path.pop_back(); // 撤销扩展动作 } } };
Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
Each number in C may only be used once in the combination.
Note:
For example, given candidate set 10,1,2,7,6,1,5
and target 8
,
A solution set is:
[1, 7] [1, 2, 5] [2, 6] [1, 1, 6]
class Solution { public: vector<vector<int> > combinationSum2(vector<int> &num, int target) { vector<vector<int>> result; if (num.size() == 0) return result; sort(num.begin(), num.end()); vector<int> path; dfs(num, target, 0, path, result); return result; } void dfs(const vector<int>& num, int gap, int start, vector<int>& path, vector<vector<int>>& result) { if (gap == 0) { // 找到一个合法解 result.push_back(path); return; } int prev = -1; for (int i = start; i < num.size(); ++i) { if (prev == num.at(i)) continue; // 确保num.at(i) 最多只用一次 if (gap < num.at(i)) return; // 剪枝 prev = num.at(i); path.push_back(num.at(i)); // 执行扩展动作 dfs(num, gap - num.at(i), i + 1, path, result); path.pop_back(); // 撤消扩展动作 } } };
Leetcode:Combination Sum 子集和问题,布布扣,bubuko.com
Leetcode:Combination Sum 子集和问题
标签:des style blog http color get
原文地址:http://www.cnblogs.com/wwwjieo0/p/3794191.html