码迷,mamicode.com
首页 > 其他好文 > 详细

XTUOJ 1206 Dormitory's Elevator

时间:2015-06-05 21:07:21      阅读:127      评论:0      收藏:0      [点我收藏+]

标签:

Dormitory‘s Elevator

Time Limit : 1000 MS   Memory Limit : 65536 KB

Problem Description

The new dormitory has N(1≤N≤100000) floors and M(1≤M≤100000)students. In the new dormitory, in order to save student‘s time as well as encourage student exercise, the elevator in dormitory will not stop in adjacent floor. So if there are people want to get off the elevator in adjacent floor, one of them must walk one stair instead. Suppose a people go down 1 floor costs A energy, go up 1 floor costs B energy(1≤A,B≤100). Please arrange where the elevator stop to minimize the total cost of student‘s walking cost.All students and elevator are at floor 1 initially, and the elevator can not godown and can stop at floor 2.

Input

First line contain an integer T, there are T(1≤T≤10) cases. For each case T, there are two lines. First line: The number of floors N(1≤N≤100000), and the number of students M(1≤M≤100000),A,B(1≤A,B≤100) Second line: M integers (2≤A[i]≤N), the student‘s desire floor.

Output

Output case number first, then the answer, the minimum of the total cost of student‘s walking cost.

Sample Input

1
3 2 1 1
2 3

Sample Output

Case 1: 1

 

Source

daizhenyang

 

解题:动态规划,同NYIST的诡异的电梯

技术分享
 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 const int maxn = 100010;
 4 int dp[maxn],des[maxn];
 5 int main(){
 6     int T,n,m,A,B;
 7     scanf("%d",&T);
 8     for(int t = 1; t <= T; ++t){
 9         memset(dp,0x3f,sizeof dp);
10         memset(des,0,sizeof des);
11         scanf("%d %d %d %d",&n,&m,&A,&B);
12         for(int i = 0,tmp; i < m; ++i){
13             scanf("%d",&tmp);
14             des[tmp]++;
15         }
16         dp[1] = dp[2] = dp[0] = 0;
17         for(int i = 3; i <= n; ++i){
18             dp[i] = dp[i-2] + min(A,B)*des[i-1];
19             int x = min(B,A*2)*des[i-2];
20             int y = min(B*2,A)*des[i-1];
21             dp[i] = min(dp[i],dp[i-3] + x + y);
22         }
23         printf("Case %d: %d\n",t,dp[n]);
24     }
25     return 0;
26 }
View Code

 

XTUOJ 1206 Dormitory's Elevator

标签:

原文地址:http://www.cnblogs.com/crackpotisback/p/4555479.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!