标签:style class blog code java ext
Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Analysis: 需求里面要求O(N)时间以及无额外空间,这就排除了使用boolean array, hashmap这些个方法,只能在原数组上进行查找。O(N)基本上就相当于遍历数组,于是我就想怎么才能遍历一遍数组就知道哪个数是single的,于是就想到了需要sort一下这个数组,寻找前后元素不一样的项。
1 public class Solution { 2 public int singleNumber(int[] A) { 3 java.util.Arrays.sort(A); 4 if (A.length == 1) return A[0]; 5 int i = 1; 6 while (i < A.length) { 7 if (A[i] != A[i-1]) return A[i-1]; 8 i += 2; 9 } 10 return A[i-1]; 11 } 12 }
Leetcode: Single Number,布布扣,bubuko.com
标签:style class blog code java ext
原文地址:http://www.cnblogs.com/EdwardLiu/p/3795723.html