标签:style class blog code http tar
我们应该通过思考得到这样一个性质:如果一个点被选了,那么与它同行同列的点都不能选
然后就是裸的二分图匹配了……
(我应该能想出这道题来的,可是看了看题觉得没思路就去看题解了,唉……以后这种水题自己一定要动脑想想!)
代码:这种水题应该1A吧
1 var i,j,n,t:longint; 2 flag:boolean; 3 p:array[0..250] of longint; 4 v:array[0..250] of boolean; 5 a:array[0..250,0..250] of longint; 6 function find(x:longint):boolean; 7 var i:longint; 8 begin 9 for i:=1 to n do 10 if (not(v[i])) and (a[x,i]=1) then 11 begin 12 v[i]:=true; 13 if (p[i]=0) or (find(p[i])) then 14 begin 15 p[i]:=x; 16 exit(true); 17 end; 18 end; 19 exit(false); 20 end; 21 procedure init; 22 begin 23 readln(n); 24 fillchar(p,sizeof(p),0); 25 for i:=1 to n do 26 begin 27 for j:=1 to n do read(a[i,j]); 28 readln; 29 end; 30 end; 31 procedure main; 32 begin 33 flag:=true; 34 for i:=1 to n do 35 begin 36 fillchar(v,sizeof(v),false); 37 if not(find(i)) then begin flag:=false;break;end; 38 end; 39 if flag then writeln(‘Yes‘) else writeln(‘No‘); 40 end; 41 42 begin 43 readln(t); 44 while t>0 do 45 begin 46 dec(t); 47 init; 48 main; 49 end; 50 end.
标签:style class blog code http tar
原文地址:http://www.cnblogs.com/zyfzyf/p/3799516.html