标签:nyoj 927
4 1 2 4 7 13 4 1 2 4 7 15
Of course,I can! Sorry,I can‘t!
#include <stdio.h> #include <stdlib.h> int n, arr[22], sum, vis[22], ok, count; const char *sam[] = {"Sorry,I can't!\n", "Of course,I can!\n"}; int cmp(const void *a, const void *b){ return *(int *)a - *(int *)b; } void DFS(int k){ if(count == sum){ ok = 1; return; } for(int i = k; i < n; ++i){ if(i && arr[i] == arr[i-1] && !vis[i-1]) //cut continue; if(count > sum && arr[i] > 0) return; //cut count += arr[i]; vis[i] = 1; DFS(i + 1); if(ok) return; count -= arr[i]; vis[i] = 0; } } int main(){ while(scanf("%d", &n) == 1){ for(int i = 0; i < n; ++i){ scanf("%d", arr + i); vis[i] = 0; } scanf("%d", &sum); qsort(arr, n, sizeof(int), cmp); count = ok = 0; DFS(0); printf(ok ? sam[1] : sam[0]); } return 0; }
NYOJ 927 The partial sum problem 【DFS】+【剪枝】,布布扣,bubuko.com
NYOJ 927 The partial sum problem 【DFS】+【剪枝】
标签:nyoj 927
原文地址:http://blog.csdn.net/chang_mu/article/details/32140951