标签:nyoj 927
4 1 2 4 7 13 4 1 2 4 7 15
Of course,I can! Sorry,I can‘t!
#include <stdio.h>
#include <stdlib.h>
int n, arr[22], sum, vis[22], ok, count;
const char *sam[] = {"Sorry,I can't!\n", "Of course,I can!\n"};
int cmp(const void *a, const void *b){
return *(int *)a - *(int *)b;
}
void DFS(int k){
if(count == sum){
ok = 1; return;
}
for(int i = k; i < n; ++i){
if(i && arr[i] == arr[i-1] && !vis[i-1]) //cut
continue;
if(count > sum && arr[i] > 0) return; //cut
count += arr[i]; vis[i] = 1;
DFS(i + 1);
if(ok) return;
count -= arr[i]; vis[i] = 0;
}
}
int main(){
while(scanf("%d", &n) == 1){
for(int i = 0; i < n; ++i){
scanf("%d", arr + i);
vis[i] = 0;
}
scanf("%d", &sum);
qsort(arr, n, sizeof(int), cmp);
count = ok = 0; DFS(0);
printf(ok ? sam[1] : sam[0]);
}
return 0;
}
NYOJ 927 The partial sum problem 【DFS】+【剪枝】,布布扣,bubuko.com
NYOJ 927 The partial sum problem 【DFS】+【剪枝】
标签:nyoj 927
原文地址:http://blog.csdn.net/chang_mu/article/details/32140951