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题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1715
5 1 2 3 4 5
1 1 2 3 5
代码如下:
//HDU 1715
#include<cstdio>
#include<iostream>
#include<cstring>
#define N 1002
using namespace std;
char Fib[N][N];
int main()
{
memset(Fib,'0',sizeof(Fib)); // 初始化
Fib[0][0]='0';
Fib[1][0]='1';
Fib[2][0]='1';
int i,j,d=1;
for(i = 3 ; i < N ; i++) //大数相加
{
d++;
int c=0,s;
for(j = 0 ; j <= d ; j++)
{
s=Fib[i-1][j]-'0'+Fib[i-2][j]-'0'+c;
c=s / 10; //进位
Fib[i][j] = s%10+'0';
}
}
int t;
//cin>>t;
scanf("%d",&t);
while(t--)
{
int n;
// cin >> n;
scanf("%d",&n);
int k=N-1;
while(k--)
{
if(Fib[n][k]!='0')
break; //去掉前面的0
}
for(i=k;i>=0;i--)
printf("%c",Fib[n][i]);
//cout<<Fib[n][i];
// cout<<endl;
printf("\n");
}
return 0;
}原文地址:http://blog.csdn.net/u012860063/article/details/32960269