标签:style class blog code ext color
Given a list, rotate the list to the right by k places, where k is non-negative. For example: Given 1->2->3->4->5->NULL and k = 2, return 4->5->1->2->3->NULL.
Anaylisis: Linked List题目的做法其实比较固定,就是Runner Technique(Two pointer) 方法加上 Dummy Node(设置一个head之前的虚假节点)两种方法,这道题就这样搞一搞就出来了。
需要注意的是:处理null 输入需要特别考虑,然后,需要找到新的linked list的头
1 /** 2 * Definition for singly-linked list. 3 * public class ListNode { 4 * int val; 5 * ListNode next; 6 * ListNode(int x) { 7 * val = x; 8 * next = null; 9 * } 10 * } 11 */ 12 public class Solution { 13 public ListNode rotateRight(ListNode head, int n) { 14 if (head == null || n == 0) return head; 15 ListNode prev = new ListNode(-1); 16 prev.next = head; 17 int size = 0; 18 ListNode current = prev; 19 ListNode runner = prev; 20 while (current.next != null) { 21 current = current.next; 22 ++size; 23 } 24 current = prev; 25 int shift = n % size; 26 for (; shift > 0; shift--) { 27 runner = runner.next; 28 } 29 while (runner.next != null) { 30 runner = runner.next; 31 current = current.next; 32 } 33 runner.next = prev.next; 34 ListNode newhead = current.next; 35 current.next = null; 36 return newhead; 37 } 38 }
Leetcode: Rotate List,布布扣,bubuko.com
标签:style class blog code ext color
原文地址:http://www.cnblogs.com/EdwardLiu/p/3805191.html