标签:des class blog code java http
Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
Each number in C may only be used once in the combination.
Note:
For example, given candidate set10,1,2,7,6,1,5and target8,
A solution set is:
[1, 7]
[1, 2, 5]
[2, 6]
[1, 1, 6]
https://oj.leetcode.com/problems/combination-sum-ii/
import java.util.ArrayList; import java.util.Arrays; public class Solution { public ArrayList<ArrayList<Integer>> combinationSum2(int[] num, int target) { ArrayList<ArrayList<Integer>> result = new ArrayList<ArrayList<Integer>>(); if (num == null || num.length == 0) return result; int n = num.length; Arrays.sort(num); ArrayList<Integer> list = new ArrayList<Integer>(); dfs(0, num, target, list, result); return result; } private void dfs(int level, int[] a, int num, ArrayList<Integer> list, ArrayList<ArrayList<Integer>> result) { if (num == 0) { result.add(new ArrayList<Integer>(list)); } else if (num < 0) return; else { for (int i = level; i < a.length; i++) { if (a[i] <= num) { list.add(a[i]); dfs(i + 1, a, num - a[i], list, result); list.remove(list.size() - 1); while (i < a.length - 1 && a[i] == a[i + 1]) i++; } } } } public static void main(String[] args) { System.out.println(new Solution().combinationSum2(new int[] { 10, 1, 2, 7, 6, 1, 5 }, 8)); System.out.println(new Solution().combinationSum2(new int[] { 1, 1, 1, 2, 2 }, 3)); } }
参考:
http://blog.csdn.net/linhuanmars/article/details/20829099
[leetcode] Combination Sum II,布布扣,bubuko.com
标签:des class blog code java http
原文地址:http://www.cnblogs.com/jdflyfly/p/3810749.html