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[leetcode] Search Insert Position

时间:2014-06-27 12:30:39      阅读:204      评论:0      收藏:0      [点我收藏+]

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Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0

https://oj.leetcode.com/problems/search-insert-position/

思路:binary search 变体,求floor。

public class Solution {

	public int searchInsert(int[] A, int target) {
		return floor(A, target);
	}

	private static int floor(int[] a, int target) {
		int low = 0;
		int high = a.length;
		int mid;
		while (low < high) {
			mid = (low + high) / 2;
			if (target > a[mid])
				low = mid + 1;
			else
				high = mid;

		}
		return low;

	}

	public static void main(String[] args) {
		System.out.println(new Solution().searchInsert(new int[]{1,3,5,6},5));
		System.out.println(new Solution().searchInsert(new int[]{1,3,5,6},2));
		System.out.println(new Solution().searchInsert(new int[]{1,3,5,6},7));
		System.out.println(new Solution().searchInsert(new int[]{1,3,5,6},0));

	}

}

 

 

[leetcode] Search Insert Position,布布扣,bubuko.com

[leetcode] Search Insert Position

标签:class   code   java   http   tar   com   

原文地址:http://www.cnblogs.com/jdflyfly/p/3810738.html

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