LINQ获取树形分类的层数

时间：2014-05-05 23:21:06 阅读：366 评论：0 收藏：0 [点我收藏+]

数据库中的数据格式：

CREATE TABLE [dbo].[T_user_department](
[id] [int] IDENTITY(1,1) NOT NULL,
[department_pid] [int] NULL,
[department_name] [nvarchar](20) NULL,
CONSTRAINT [PK_T_USER_DEPARTMENT] PRIMARY KEY CLUSTERED
(
[id] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
SET IDENTITY_INSERT [dbo].[T_user_department] ON
INSERT [dbo].[T_user_department] ([id], [department_pid], [department_name]) VALUES (1, 0, N‘技术部‘)
INSERT [dbo].[T_user_department] ([id], [department_pid], [department_name]) VALUES (2, 0, N‘ 销售部‘)
INSERT [dbo].[T_user_department] ([id], [department_pid], [department_name]) VALUES (3, 2, N‘销售1部‘)
INSERT [dbo].[T_user_department] ([id], [department_pid], [department_name]) VALUES (4, 2, N‘销售2部‘)
INSERT [dbo].[T_user_department] ([id], [department_pid], [department_name]) VALUES (5, 0, N‘客服部‘)
INSERT [dbo].[T_user_department] ([id], [department_pid], [department_name]) VALUES (6, 3, N‘人事部‘)
SET IDENTITY_INSERT [dbo].[T_user_department] OFF
ALTER TABLE [dbo].[T_user_department] ADD DEFAULT ((0)) FOR [department_pid]

树形格式（为了直观，按id排列）

获取层数的测试代码：

#region
// Admin/Account/Admin/GetDepartmentData
public string GetDepartmentData(int id)
{
return GetLayerById(id).ToString();
}
/// <summary>
/// 获取分类的层数
/// </summary>
/// <param name="id">根据id获取树的层数</param>
/// <returns>树的层数</returns>
private int GetLayerById(int id)
{
int layer = 1;
for (int subId =(int)db.TUserDepartments.Where(d=>d.id==id).Select(d=>d.department_pid).ToList().FirstOrDefault(); subId != 0; )
{
subId = (int)db.TUserDepartments.Where(d => d.id == subId).Select(d => d.department_pid).ToList().FirstOrDefault();
layer++;
}
return layer;
}
#endregion

原文地址：http://www.cnblogs.com/tangyouwei/p/3704584.html

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