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[leetcode] Climbing Stairs

时间:2014-07-08 00:12:04      阅读:171      评论:0      收藏:0      [点我收藏+]

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You are climbing a stair case. It takes n steps to reach to the top.

Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

https://oj.leetcode.com/problems/climbing-stairs/

 

分析:Fibonacci数列,不要用递推,重复计算太多,用DP。

bubuko.com,布布扣
public class Solution {
    public int climbStairs(int n) {
        if(n<=0)
            return 0;
        if(n==1)
            return 1;
        if(n==2)
            return 2;
        
        int i;
        int firstWays=1;
        int secondWays=2;
        int ways=0;
        for(i=3;i<=n;i++){
            ways=firstWays+secondWays;
            firstWays=secondWays;
            secondWays=ways;
        }
        
        return ways;
            
    }
}
View Code

 

[leetcode] Climbing Stairs,布布扣,bubuko.com

[leetcode] Climbing Stairs

标签:style   blog   http   color   os   art   

原文地址:http://www.cnblogs.com/jdflyfly/p/3812628.html

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