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[leetcode] Search in Rotated Sorted Array II

时间:2014-07-07 13:07:00      阅读:153      评论:0      收藏:0      [点我收藏+]

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Follow up for "Search in Rotated Sorted Array":
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Write a function to determine if a given target is in the array.

https://oj.leetcode.com/problems/search-in-rotated-sorted-array-ii/

 

思路:类似Search in Rotated Sorted Array的思路,只不过现在的问题是有重复,可能出现a[l]==a[m]的极端情况,无法判断哪半边有序,因此这种情况下只能一步一步移动l 直到不相等然后通过二分判断。

复杂度:极端情况每次都是减一 而不是减去一半,所以复杂度是O(N)。

 

bubuko.com,布布扣
/**
 * http://blog.csdn.net/linhuanmars/article/details/20525681
 * 
 * @author jd
 * 
 */

public class Solution {
    public boolean search(int[] A, int target) {
        if (A == null || A.length == 0)
            return false;
        int l = 0;
        int r = A.length - 1;
        while (l <= r) {
            int m = (l + r) / 2;
            if (A[m] == target)
                return true;
            if (A[m] > A[l]) {
                if (A[m] > target && A[l] <= target) {
                    r = m - 1;
                } else {
                    l = m + 1;
                }
            } else if (A[m] < A[l]) {
                if (A[m] < target && A[r] >= target) {
                    l = m + 1;
                } else {
                    r = m - 1;
                }
            } else {
                l++;
            }
        }
        return false;
    }

    public static void main(String[] args) {

        System.out.println(new Solution().search(new int[] { 3, 1, 1 }, 3));

        System.out.println(new Solution().search(new int[] { 2, 3, 3, 3, 3 }, 2));
        System.out.println(new Solution().search(new int[] { 3, 2, 3, 3, 3 }, 2));
        System.out.println(new Solution().search(new int[] { 3, 3, 3, 2, 3 }, 2));
        System.out.println(new Solution().search(new int[] { 3, 3, 3, 3, 2 }, 2));

    }

}
View Code

 

参考:

http://blog.csdn.net/linhuanmars/article/details/20525681

 

[leetcode] Search in Rotated Sorted Array II,布布扣,bubuko.com

[leetcode] Search in Rotated Sorted Array II

标签:style   blog   http   color   os   art   

原文地址:http://www.cnblogs.com/jdflyfly/p/3815510.html

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