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0 1 0 0
OK
#include<stdio.h>
main(){
int m,i,n,a,sign,j;
while(scanf("%d%d",&m,&n)!=EOF&&(m!=0||n!=0))
{
sign=0;
for(i=m;i<=n;i++)
{
a=i*i+i+41;
for(j=2;j<a/2;j++)
{
if(a%j==0)
{sign=1;break;}
}
}
if(sign==0)
{printf("OK\n");}
else
{printf("Sorry\n");}
}
}
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原文地址:http://blog.csdn.net/hncu1306602liuqiang/article/details/46388169