动态构造结构体数组

# include <stdio.h>
# include <malloc.h>

struct Student
{
    int age;
    float score;
    char name[100];
};

int main(void)
{
    int len;
    struct Student * pArr;
    int i, j;
    struct Student t;
    

    //动态的构造一维数组
    printf("请输入学生的个数:\n");
    printf("len = ");
    scanf("%d", &len);
    pArr = (struct Student *)malloc(len * sizeof(struct Student));
    
    //输入
    for (i=0; i<len; ++i)
    {
        printf("请输入第%d个学生的信息:\n", i+1);
        printf("age = ");
        scanf("%d", &pArr[i].age);

        printf("name = ");
        scanf("%s", pArr[i].name);  //name是数组名，本身就已经是数组首元素的地址, 所以pArr[i].name 不能改成 &pArr[i].name

        printf("score = ");
        scanf("%f", &pArr[i].score);
    }

    //按学生成绩升序排序 冒泡算法
    for (i=0; i<len-1; ++i)
    {
        for (j=0; j<len-1-i; ++j)
        {
            if (pArr[j].score > pArr[j+1].score) //>升序 <降序
            {
                t = pArr[j];
                pArr[j] = pArr[j+1];
                pArr[j+1] = t;
            }
        }
    }

    printf("\n\n学生的信息是:\n");
    //输出
    for (i=0; i<len; ++i)
    {
        printf("第%d个学生的信息是:\n", i+1);
        printf("age = %d\n", pArr[i].age);
        printf("name = %s\n", pArr[i].name);  //name是数组名，本身就已经是数组首元素的地址, 所以pArr[i].name 不能改成 &pArr[i].name
        printf("score = %f\n", pArr[i].score);
    
        printf("\n");
    }

    return 0;
}