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Given a string containing just the characters ‘(‘, ‘)‘, ‘{‘, ‘}‘, ‘[‘ and ‘]‘, determine if the input string is valid. The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]" are not.
题解分析:
对每一个括号进行判断:
如果是 左括号:入栈
如果是 右括号:出栈,并且判断栈顶元素 与 当前遍历括号 是否为一对匹配的括号
如果是,则继续遍历,如果不是,则返回false
class Solution { public: bool isValid(string s) { stack<char> stk; stk.push(‘#‘); for (int i = 0; i < s.size(); ++i) { if (isLeft(s.at(i))) { stk.push(s.at(i)); } else { if (isPair(stk.top(), s.at(i))) { stk.pop(); } else { return false; } } } return stk.top() == ‘#‘; } bool isLeft(char c) { if (c == ‘(‘ || c == ‘{‘ || c == ‘[‘) { return true; } else { return false; } } bool isPair(char a, char b) { return (a == ‘(‘ && b == ‘)‘) || (a == ‘{‘ && b == ‘}‘) || (a == ‘[‘ && b == ‘]‘); } };
Leetcode: Valid Parentheses 有效的括号匹配,布布扣,bubuko.com
Leetcode: Valid Parentheses 有效的括号匹配
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原文地址:http://www.cnblogs.com/wwwjieo0/p/3816827.html