标签：周赛
Description
Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he‘s earned fair and square, he has to open the lock.
The combination lock is represented by n rotating disks with digits from 0 to 9 written on them. Scrooge McDuck has to turn some disks so that the combination of digits on the disks forms a secret combination. In one move, he can rotate one disk one digit forwards or backwards. In particular, in one move he can go from digit 0 to digit 9 and vice versa. What minimum number of actions does he need for that?
Input
The first line contains a single integer n (1?≤?n?≤?1000) — the number of disks on the combination lock.
The second line contains a string of n digits — the original state of the disks.
The third line contains a string of n digits — Scrooge McDuck‘s combination that opens the lock.
Output
Print a single integer — the minimum number of moves Scrooge McDuck needs to open the lock.
Sample Input
5 82195 64723
13
Hint
In the sample he needs 13 moves:
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
int n;
char a[1100];
char b[1100];
int flag= 0 ;
cin >> n;
for (int i=0; i<n; i++)
cin >> a[i];
for (int j=0; j<n; j++)
cin >> b[j];
int num = 0;
for (int i=0; i<n; i++)
{
int p1 = (int)a[i]-48;
int p2 = (int)b[i]-48;
int p = p1-p2;
flag = abs(p);
if (flag>5)
flag = 10-flag;
num = num +flag;
}
cout << num << endl;
return 0;
}标签：周赛
原文地址：http://blog.csdn.net/xiaotan1314/article/details/46399531
