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南阳122(Triangular Sums)

时间:2015-06-08 00:55:50      阅读:184      评论:0      收藏:0      [点我收藏+]

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Triangular Sums

时间限制:3000 ms  |  内存限制:65535 KB
难度:2
 
描述

The nth Triangular number, T(n) = 1 + … + n, is the sum of the first n integers. It is the number of points in a triangular array with n points on side. For example T(4):

X
X X
X X X
X X X X

Write a program to compute the weighted sum of triangular numbers:

W(n) = SUM[k = 1…nk * T(k + 1)]

 
输入
The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.

Each dataset consists of a single line of input containing a single integer n, (1 ≤ n ≤300), which is the number of points on a side of the triangle.
输出
For each dataset, output on a single line the dataset number (1 through N), a blank, the value of n for the dataset, a blank, and the weighted sum ,W(n), of triangular numbers for n.
样例输入
4
3
4
5
10

 

样例输出
1 3 45
2 4 105
3 5 210
4 10 2145

 

来源
Greater New York 2006
//T(N)=1+2+3+.....+N ; SUM=1*T(2)+2*T(3)+3*T(4)+......N*T(N+1)
 1 #include<stdio.h>
 2 int main() 
 3 {
 4     int m,i;
 5     scanf("%d",&m);
 6     for(i=1;i<=m;i++)
 7     {
 8         int num,sum=0,total=1;
 9         scanf("%d",&num);
10         for(int j=2;j<=num+1;j++)
11         {                
12             total+=j; 
13             sum+=total*(j-1);
14         }    
15         printf("%d %d %d\n",i,num,sum);        
16     }
17     return 0;
18 }

 //看懂题意后,水;

南阳122(Triangular Sums)

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原文地址:http://www.cnblogs.com/fengshun/p/4559734.html

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