Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
if (head == null || head.next == null) {
return false;
}
ListNode first = head;
ListNode second = head;
while (second != null) {
second = second.next;
if (second != null) {
second = second.next;
} else {
return false;
}
first = first.next;
if (second == first) {
return true;
}
}
return false;
}
}Linked List Cycle,布布扣,bubuko.com
原文地址:http://blog.csdn.net/u010378705/article/details/36025403