Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
/** * Definition for singly-linked list. * class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ public class Solution { public boolean hasCycle(ListNode head) { if (head == null || head.next == null) { return false; } ListNode first = head; ListNode second = head; while (second != null) { second = second.next; if (second != null) { second = second.next; } else { return false; } first = first.next; if (second == first) { return true; } } return false; } }
Linked List Cycle,布布扣,bubuko.com
原文地址:http://blog.csdn.net/u010378705/article/details/36025403