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Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 32717 Accepted Submission(s):
14482
#include<stdio.h> #include<string.h> #define MAX 21 int a[MAX]; int vis[MAX]; int prime[50]; int k; void biao() { int i,j; for(i=0;i<=50;i++) prime[i]=1; for(i=2;i<=50;i++) { if(prime[i]) { for(j=2*i;j<=50;j+=i) { prime[j]=0; } } } prime[1]=0; } void dfs(int cur,int n) { int i,j; if(cur==n+1&&prime[1+a[n]]) { for(i=1;i<=n;i++) { if(i==1) printf("%d",a[i]); else printf(" %d",a[i]); } printf("\n"); } else { for(i=2;i<=n;i++) { if(!vis[i]&&prime[i+a[cur-1]]) { a[cur]=i; vis[i]=1; dfs(cur+1,n); vis[i]=0; } } } } int main() { int n,m,j,i,t; biao(); k=1; while(scanf("%d",&n)!=EOF) { memset(a,0,sizeof(a)); memset(vis,0,sizeof(vis)); a[1]=1;vis[1]=1; printf("Case %d:\n",k++); if(n==1) printf("1\n"); else dfs(2,n); printf("\n"); } return 0; }
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原文地址:http://www.cnblogs.com/tonghao/p/4564454.html