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Description
If you think codes, eat codes then sometimes you may get stressed. In your dreams you may see huge codes, as I have seen once. Here is the code I saw in my dream.
#include <stdio.h>
int cases, caseno;
int n, K, MOD;
int A[1001];
int main() {
scanf("%d", &cases);
while( cases-- ) {
scanf("%d %d %d", &n, &K, &MOD);
int i, i1, i2, i3, ... , iK;
for( i = 0; i < n; i++ ) scanf("%d", &A[i]);
int res = 0;
for( i1 = 0; i1 < n; i1++ ) {
for( i2 = 0; i2 < n; i2++ ) {
for( i3 = 0; i3 < n; i3++ ) {
...
for( iK = 0; iK < n; iK++ ) {
res = ( res + A[i1] + A[i2] + ... + A[iK] ) % MOD;
}
...
}
}
}
printf("Case %d: %d\n", ++caseno, res);
}
return 0;
}
Actually the code was about: ‘You are given three integers n, K, MOD and n integers: A0, A1, A2 ... An-1, you have to write K nested loops and calculate the summation of all Ai where i is the value of any nested loop variable.‘
Input
Input starts with an integer T (≤ 100), denoting the number of test cases.
Each case starts with three integers: n (1 ≤ n ≤ 1000), K (1 ≤ K < 231), MOD (1 ≤ MOD ≤ 35000). The next line contains n non-negative integers denoting A0, A1, A2 ... An-1. Each of these integers will be fit into a 32 bit signed integer.
Output
For each case, print the case number and result of the code.
Sample Input
2
3 1 35000
1 2 3
2 3 35000
1 2
Sample Output
Case 1: 6
Case 2: 36
#include<iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<algorithm> #include<vector> #include<stack> #include<queue> #include<set> #include<map> #include<string> #include<math.h> #include<cctype> using namespace std; typedef long long ll; const int maxn=1000100; const int INF=(1<<29); const double EPS=0.0000000001; const double Pi=acos(-1.0); int T; int n; ll k,p,a; ll qpow(ll n,ll k) { ll res=1; while(k){ if(k&1) res=((res%p)*(n%p))%p; n=(n%p)*(n%p)%p; k>>=1; } return res; } int main() { cin>>T; int tag=1; while(T--){ cin>>n>>k>>p; ll sum=0; for(int i=1;i<=n;i++) scanf("%lld",&a),sum=(a%p+sum%p)%p; cout<<"Case "<<tag++<<": "<<sum*qpow(n,k-1)*(k%p)%p<<endl; } return 0; }
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原文地址：http://www.cnblogs.com/--560/p/4564806.html
