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这里贴个模板吧。反正是不太理解
看原题就可以理解用法!!
#include <cstdio> #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include <map> using namespace std; #define Times 10 typedef __int64 LL; map<LL,int>m; LL Random(LL n) { return ((double)rand()/RAND_MAX*n+0.5); } LL multi(LL a,LL b,LL mod) { LL ans=0; while(b) { if(b&1) { b--; ans=(ans+a)%mod; } else { b/=2; a=(a+a)%mod; } } return ans; } LL Pow(LL a,LL b,LL mod) { LL ans=1; while(b) { if(b&1) { b--; ans=multi(ans,a,mod); } else { b/=2; a=multi(a,a,mod); } } return ans; } bool witness(LL a,LL n) { LL d=n-1; while(!(d&1)) d>>=1; LL t=Pow(a,d,n); while(d!=n-1 && t!=1 && t!=n-1) { t=multi(t,t,n); d<<=1; } return t==n-1 || d&1; } bool miller_rabin(LL n) { if(n==2) return true; if(n<2||!(n&1)) return false; for(int i=1;i<=Times;i++) { LL a=Random(n-2)+1; if(!witness(a,n)) return false; } return true; } LL gcd(LL a,LL b) { if(b==0) return a; return gcd(b,a%b); } LL pollard_rho(LL n,LL c) { LL x,y,d,i=1,k=2; x=Random(n-1)+1; y=x; while(1) { i++; x=(multi(x,x,n)+c)%n; d=gcd(y-x,n); if(1<d&&d<n) return d; if(y==x) return n; if(i==k) { y=x; k<<=1; } } } void find(LL n,LL c) { if(n==1) return ; if(miller_rabin(n)) { m[n]++; return ; } LL p=n; while(p>=n) p=pollard_rho(p,c--); find(p,c); find(n/p,c); } int main() { int t; cin>>t; while(t--) { LL n; cin>>n; m.clear(); find(n,2013724); if(m.size()==1) cout<<1<<" "<<n/m.begin()->first<<endl; else { LL ans=0; map<LL,int>::iterator it=m.begin(); for(;it!=m.end();it++) ans+=Pow(it->first,it->second,n); cout<<m.size()<<" "<<ans<<endl; } } return 0; }
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原文地址:http://www.cnblogs.com/Commence/p/4569877.html