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Description
Input
Output
Sample Input
2 3 2 1 1 10 3 3 9 1
Sample Output
Case 1: 3 Case 2: 14
然后是通过线段树的标记功能
/*
Problem : 4217 ( Data Structure? ) Judge Status : Accepted
RunId : 13881893 Language : C++ Author : 24862486
Timer : 998ms
Code Render Status : Rendered By HDOJ C++ Code Render Version 0.01 Beta
*/
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
#define lson rt << 1 , L , mid
#define rson rt << 1 | 1 , mid + 1 , R
const int maxn=262144+5;
int n,k,ki,T;
int sum[maxn<<2];
void pushup(int rt) {
sum[rt]=sum[rt<<1]+sum[rt<<1|1];
}
void build(int rt,int L,int R) {
if(L==R) {
sum[rt]=1;
return;
}
int mid=(L+R)>>1;
build(lson);
build(rson);
pushup(rt);
}
int query(int p,int rt,int L,int R) {
if(L==R) {
sum[rt]=0;
return R;
}
int mid=(L+R)>>1;
int res;
if(sum[rt<<1]>=p)res=query(p,lson);//向终点靠拢
else res=query(p-sum[rt<<1],rson);
pushup(rt);
return res;
}
int main() {
scanf("%d",&T);
for(int t=1; t<=T; t++) {
scanf("%d%d",&n,&k);
build(1,1,n);
long long res=0;
for(int i=0; i<k; i++) {
scanf("%d",&ki);
res+=query(ki,1,1,n);
}
printf("Case %d: %lld\n",t,res);
}
return 0;
}
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原文地址:http://blog.csdn.net/qq_18661257/article/details/46468459