码迷,mamicode.com
首页 > 其他好文 > 详细

cf307 div2 E 未AC代码

时间:2015-06-13 06:19:22      阅读:123      评论:0      收藏:0      [点我收藏+]

标签:

#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
#include <map>
#include <stack>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define test freopen("test.txt","r",stdin)  
#define maxn 2000001
#define mod 10007
#define eps 1e-9
const int inf=0x3f3f3f3f;
const ll infll = 0x3f3f3f3f3f3f3f3fLL;
inline ll read()
{
    ll x=0,f=1;char ch=getchar();
    while(ch<0||ch>9){if(ch==-)f=-1;ch=getchar();}
    while(ch>=0&&ch<=9){x=x*10+ch-0;ch=getchar();}
    return x*f;
}
//**************************************************************************************

ll n,q,m,block;
ll a[1000001],b[1000001],pos[1000001],add[1000001];
void reset(ll x)
{
    ll l=(x-1)*block+1,r=min(x*block,n);
    for(ll i=l;i<=r;i++)
        b[i]=a[i];
    sort(b+l,b+r+1);
}
ll find(ll x,ll v)
{
    ll l=(x-1)*block+1,r=min(x*block,n);
    ll last=r;
    while(l<=r)
    {
        ll mid=(l+r)>>1;
        if(b[mid]<v)l=mid+1;
        else r=mid-1;
    }
    return last-l+1;
}
void update(ll x,ll y,ll v)
{
    if(pos[x]==pos[y])
    {
        for(int i=x;i<=y;i++)a[i]=a[i]+v;
    }
    else 
    {
        for(int i=x;i<=pos[x]*block;i++)a[i]=a[i]+v;
        for(int i=(pos[y]-1)*block+1;i<=y;i++)a[i]=a[i]+v;
    }
    reset(pos[x]);reset(pos[y]);
    for(int i=pos[x]+1;i<pos[y];i++)
       add[i]+=v;
}
ll query(ll x,ll y,ll v)
{
    ll sum=0;
    if(pos[x]==pos[y])
    {
        for(int i=x;i<=y;i++)if(a[i]+add[pos[i]]>=v)sum++;
    }
    else 
    {
        for(int i=x;i<=pos[x]*block;i++)
            if(a[i]+add[pos[i]]>=v)sum++;
        for(int i=(pos[y]-1)*block+1;i<=y;i++)
            if(a[i]+add[pos[i]]>=v)sum++;
    }
    for(int i=pos[x]+1;i<pos[y];i++)
        sum+=find(i,v-add[i]);
    return sum;
}
int deall(int l,int r,ll c)
{
    if(l==r)
        return l;
    int mid=(l+r)>>1;
    if(query(l,mid,c)-query(l,mid,c+1)>0)
        return deall(l,mid,c);
    else
        return deall(mid+1,r,c);
    
}
int dealr(int l,int r,ll c)
{
    if(l==r)
        return l;
    int mid=(l+r)>>1;
    if(query(mid+1,r,c)-query(mid+1,r,c+1)>0)
        return dealr(mid+1,r,c);
    else
        return dealr(l,mid,c);
}
int ask(ll cc)
{
    int aa=query(1,n,cc),bb=query(1,n,cc+1);
    if(aa-bb==0)
        return -1;
    if(aa-bb==1)
        return 0;
    return dealr(1,n,cc)-deall(1,n,cc);
}
int main()
{
    //test;
    n=read(),q=read();
    block=int(sqrt(n));
    for(int i=1;i<=n;i++)
    {
        a[i]=read();
        pos[i]=(i-1)/block+1;
        b[i]=a[i];
    }
    int x,y,v;
    if(n%block)m=n/block+1;
    else m=n/block;
    for(int i=1;i<=m;i++)reset(i);
    for(int i=1;i<=q;i++)
    {
       int ch;
       ch=read();
        if(ch==1)
        {
            x=read(),y=read(),v=read();
            update(x,y,v);
        }
        else
        {
            int p;
            p=read();
            printf("%d\n",ask(p));
        }
    }
    return 0;
}

 

cf307 div2 E 未AC代码

标签:

原文地址:http://www.cnblogs.com/qscqesze/p/4572910.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!