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N*N matrix is given with input red or black.You can move horizontally, vertically or diagonally. If 3 consecutive samecolor found, that color will get 1 point. So if 4 red are vertically then pointis 2. Find the winner.
def tic_tac_toe(board,n) red, black =0, 0 n.times do |i| n.times do |j| if board[i][j] red += 1 if i<m-2 and board[i+1][j] and board[i+2][j] red += 1 if j<n-2 and board[i][j+1] and board[i][j+2] red += 1 if i<m-2 and j<n-2 and board[i+1][j+1] and board[i+2][j+2] red += 1 if i>=2 and j>=2 and board[i-1][j-1] and board[i-2][j-2] else black += 1 if i<m-2 and !board[i+1][j] and !board[i+2][j] black += 1 if j<n-2 and !board[i][j+1] and !board[i][j+2] black += 1 if i<m-2 and j<n-2 and !board[i+1][j+1] and !board[i+2][j+2] black += 1 if i>=2 and j>=2 and !board[i-1][j-1] and !board[i-2][j-2] end end end red > black end
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原文地址:http://www.cnblogs.com/lilixu/p/4573002.html